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How much power is dissipated by a light bulb if its applied voltage is 12 V and its resistance is 12 Ω?

Question

How much power is dissipated by a light bulb if its applied voltage is 12 V and its resistance is 12 Ω?

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Solution

The power P dissipated in an electrical circuit is given by the formula:

P = V^2 / R

where:

  • P is the power in watts,
  • V is the voltage in volts, and
  • R is the resistance

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