How much energy is stored in a fully charged capacitor with 1.2 × 10^−9 C of charge on one plate and 16 V across its plates?*1 point9.6 x 10^9 J9.6 x 10^-9 J96 x 10^-9 JNone of the above
Question
How much energy is stored in a fully charged capacitor with 1.2 × 10^−9 C of charge on one plate and 16 V across its plates?*1 point9.6 x 10^9 J9.6 x 10^-9 J96 x 10^-9 JNone of the above
Solution
The energy (E) stored in a capacitor can be calculated using the formula:
E = 1/2 * Q * V
where: Q is the charge on one plate of the capacitor, and V is the voltage across the plates of the capacitor.
Given: Q = 1.2 × 10^-9 C V = 16 V
Substituting these values into the formula, we get:
E = 1/2 * (1.2 × 10^-9 C) * (16 V)
E = 9.6 x 10^-9 J
So, the energy stored in the capacitor is 9.6 x 10^-9 J.
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