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correct answerWhat will be the output of the following Python code?def maxnumber(x, y):  if x > y:    print(x, 'is maximum')  elif x == y:    print(x, 'is equal to', y)  else:    print(x, 'is maximum')maxnumber(1, 2)

Question

correct answerWhat will be the output of the following Python code?def maxnumber(x, y):  if x > y:    print(x, 'is maximum')  elif x == y:    print(x, 'is equal to', y)  else:    print(x, 'is maximum')maxnumber(1, 2)

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Solution

The output of the given Python code will be "1 is maximum". This is because the function maxnumber() is designed to compare two numbers, x and y. If x is greater than y, it prints that x is the maximum. If x is equal to y, it prints that x is equal to y. However, if y is greater than x, it incorrectly prints that x is the maximum. In this case, since 1 is less than 2, it should print "2 is maximum", but due to the error in the code, it will print "1 is maximum".

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Similar Questions

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