Raised cosine (RC) pulses satisfy the Nyquist criterion of zero-ISI at sampling intervals and are derived from Sinc pulses. Question 1Select one:TrueFalse

Raised cosine (RC) pulses may be used in preference to sinc() pulses becauseQuestion 3Select one:RC pulses can be used for multilevel signallingRC pulses concentrate more signal energy in a smaller frequency range It means that sampling is less sensitive to timing errorsRC pulses have a narrower frequency bandwidth

Compared with a sinc() shaped Nyquist pulse, the Raised Cosine, or RC, pulse (with non-zero rolloff factor) has the following advantage:Question 4AnswerThe time-domain ripples have a smaller amplitudeThe time delay is shorterThe bandwidth is smallerThe OOB emissions are reduced

The use of Nyquist pulses is aimed at achieving (near) zero ISIQuestion 1Answerat the point where noise is added to the incoming signalin the transmitted pulses on the transmission channelat the point of detection in the receiverafter detection of the transmitted binary bit(s)

Consider a continuous time periodic signal𝑦(𝑡) = 6 cos(23𝜋𝑡) + 3 sin(16𝜋𝑡)(a) State the Nyquist sampling rate of y(t).(b) Regardless of your answer in (a), assume sampling frequency fs = 5Hz. Write down the sampled data y[n] for n =0, 1, . . . , 9. Suppose y[0] = y(0). (Give your answers correct to two decimal places)(c) Consider the following quantizer𝑄(𝑥) = {6,2,−2,−6,𝑥 ≥ 40 ≤ 𝑥 < 4−4 ≤ 𝑥 < 0𝑥 < −4Write down the quantized samples v[n] = Q(y[n])(d) Compute the quantization error q[n] = v[n] − y[n].(e) Under the conditions set above, determine the length of bit stream required to store y(t) for 8 seconds.

𝑦(𝑡) = 6 cos(23𝜋𝑡) + 3 sin(16𝜋𝑡)(a) State the Nyquist sampling rate of y(t).(b) Regardless of your answer in (a), assume sampling frequency fs = 5Hz. Write down the sampled data y[n] for n =0, 1, . . . , 9. Suppose y[0] = y(0). (Give your answers correct to two decimal place