What is the magnitude of vector -3i + 5j?A√34B√32C√8D√16

To find the magnitude of the vector $-3i + 5j$, we use the formula for the magnitude of a vector in two dimensions, which is given by:

$\text{Magnitude} = \sqrt{a^2 + b^2}$

where $a$ and $b$ are the components of the vector. In this case, the vector is $-3i + 5j$, so $a = -3$ and $b = 5$.

Step-by-step solution:

1. Square the components: $(-3)^2 = 9$ $5^2 = 25$

2. Add the squared components: $9 + 25 = 34$

3. Take the square root of the sum: $\sqrt{34}$

So, the magnitude of the vector $-3i + 5j$ is $\sqrt{34}$.

Therefore, the correct answer is: A) $\sqrt{34}$