The `malloc(sizeof(int) * 4)` statement will allocate 16 bytes on a 64-bit machine. Here's the step-by-step explanation:

1. `sizeof(int)`: This is a function in C that returns the size of the data type. On a 64-bit machine, the size of an integer is typically 4 bytes.

2. `sizeof(int) * 4`: This multiplies the size of an integer (4 bytes) by 4, which equals 16 bytes.

3. `malloc(sizeof(int) * 4)`: This is a function in C that dynamically allocates memory. In this case, it's allocating 16 bytes of memory.

Question

The `malloc(sizeof(int) * 4)` statement will allocate 16 bytes on a 64-bit machine. Here's the step-by-step explanation:

1. `sizeof(int)`: This is a function in C that returns the size of the data type. On a 64-bit machine, the size of an integer is typically 4 bytes.

2. `sizeof(int) * 4`: This multiplies the size of an integer (4 bytes) by 4, which equals 16 bytes.

3. `malloc(sizeof(int) * 4)`: This is a function in C that dynamically allocates memory. In this case, it's allocating 16 bytes of memory.

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The `malloc(sizeof(int) * 4)` statement will allocate 16 bytes on a 64-bit machine. Here's the step-by-step explanation:

1. `sizeof(int)`: This is a function in C that returns the size of the data type. On a 64-bit machine, the size of an integer is typically 4 bytes.

2. `sizeof(int) * 4`: This multiplies the size of an integer (4 bytes) by 4, which equals 16 bytes.

3. `malloc(sizeof(int) * 4)`: This is a function in C that dynamically allocates memory. In this case, it's allocating 16 bytes of memory.

CHow many bytes will this statement allocate on a 64-bit machine?malloc(sizeof(int) * 4)