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Which code is best to provide the age of each students recorded in the tblstudents?Group of answer choicesSELEC YEAR(NOW()) - YEAR(BDATE) FROM TBLSTUDENTSSELECT STUDNAME AS "NAME OF THE STUDENT", YEAR(NOW()) - YEAR(BDATE) FROM TBLSTUDENTSSELECT YEAR(NOW()) - YEAR(BDATE) AS AGE FROM TBLSTUDENTSSELECT STUDNAME AS "NAME OF THE STUDENT", YEAR(NOW()) - YEAR(BDATE) AS AGE FROM TBLSTUDENTS

Question

Which code is best to provide the age of each students recorded in the tblstudents?Group of answer choicesSELEC YEAR(NOW()) - YEAR(BDATE) FROM TBLSTUDENTSSELECT STUDNAME AS "NAME OF THE STUDENT", YEAR(NOW()) - YEAR(BDATE) FROM TBLSTUDENTSSELECT YEAR(NOW()) - YEAR(BDATE) AS AGE FROM TBLSTUDENTSSELECT STUDNAME AS "NAME OF THE STUDENT", YEAR(NOW()) - YEAR(BDATE) AS AGE FROM TBLSTUDENTS

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Solution

The best code to provide the age of each student recorded in the tblstudents is:

SELECT STUDNAME AS "NAME OF THE STUDENT", YEAR(NOW()) - YEAR(BDATE) AS AGE FROM TBLSTUDENTS

This code not only calculates the age of each student by subtracting the year of birth (BDATE) from the current year (YEAR(NOW())), but also includes the student's name (STUDNAME) in the output. The AS keyword is used to rename the columns in the output for better readability.

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