Liquid nitrogen boils at –195.8°C. Express the boiling point of liquid nitrogen in kelvin.–469.0 K–77.4 Kall temperatures are 0 K on the Kelvin scale77.4 K469.0 K
Question
Liquid nitrogen boils at –195.8°C. Express the boiling point of liquid nitrogen in kelvin.–469.0 K–77.4 Kall temperatures are 0 K on the Kelvin scale77.4 K469.0 K
Solution
The boiling point of liquid nitrogen in Kelvin can be calculated using the formula:
K = °C + 273.15
Given that the boiling point of liquid nitrogen is -195.8°C, we substitute this value into the formula:
K = -195.8°C + 273.15 = 77.35 K
So, the boiling point of liquid nitrogen in Kelvin is approximately 77.4 K.
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