The complex [M(ab)3] has a coordination number of 6 and is octahedral in shape. The bidentate ligand (ab) can attach to the metal ion (M) in two different ways because it has two different donor sites.

Step 1: Identify the possible arrangements of the ligands.

In this case, the ligand can attach to the metal ion in two different ways, either through the 'a' donor site or the 'b' donor site.

Step 2: Calculate the number of geometrical isomers.

For a complex of the type [M(ab)3], the number of geometrical isomers is given by the formula 2^n, where n is the number of bidentate ligands.

In this case, n = 3, so the number of geometrical isomers is 2^3 = 8.

Therefore, there are 8 possible geometrical isomers for the complex [M(ab)3] where (ab) is a bidentate ligand with different donor sites like glycinate.

Question

The complex [M(ab)3] has a coordination number of 6 and is octahedral in shape. The bidentate ligand (ab) can attach to the metal ion (M) in two different ways because it has two different donor sites.

Step 1: Identify the possible arrangements of the ligands.

In this case, the ligand can attach to the metal ion in two different ways, either through the 'a' donor site or the 'b' donor site.

Step 2: Calculate the number of geometrical isomers.

For a complex of the type [M(ab)3], the number of geometrical isomers is given by the formula 2^n, where n is the number of bidentate ligands.

In this case, n = 3, so the number of geometrical isomers is 2^3 = 8.

Therefore, there are 8 possible geometrical isomers for the complex [M(ab)3] where (ab) is a bidentate ligand with different donor sites like glycinate.

Knowee AI · Accepted Answer

The complex [M(ab)3] has a coordination number of 6 and is octahedral in shape. The bidentate ligand (ab) can attach to the metal ion (M) in two different ways because it has two different donor sites.

Step 1: Identify the possible arrangements of the ligands.

In this case, the ligand can attach to the metal ion in two different ways, either through the 'a' donor site or the 'b' donor site.

Step 2: Calculate the number of geometrical isomers.

For a complex of the type [M(ab)3], the number of geometrical isomers is given by the formula 2^n, where n is the number of bidentate ligands.

In this case, n = 3, so the number of geometrical isomers is 2^3 = 8.

Therefore, there are 8 possible geometrical isomers for the complex [M(ab)3] where (ab) is a bidentate ligand with different donor sites like glycinate.

Find out the total number of geometrical isomers possible for [M(ab)3] where (ab) is bidentate ligand having different donor sites like glycinate.

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