The question seems to be missing the table or the current probability values for the discrete random variable X. However, I can tell you the general rule for creating a legitimate probability distribution.

A legitimate probability distribution for a discrete random variable X must satisfy two conditions:

1. Each individual probability P(X=x), where x is any value that the random variable can take, must be between 0 and 1, inclusive. That is, 0 ≤ P(X=x) ≤ 1.

2. The sum of all individual probabilities must be equal to 1. That is, Σ P(X=x) = 1, where the sum is over all possible values of X.

So, for your case, where X can take the values -1, 0, 4, 5, and 6, you need to find the probabilities P(X=-1), P(X=0), P(X=4), P(X=5), and P(X=6) such that each of these probabilities is between 0 and 1, and their sum is equal to 1.

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The question seems to be missing the table or the current probability values for the discrete random variable X. However, I can tell you the general rule for creating a legitimate probability distribution.

A legitimate probability distribution for a discrete random variable X must satisfy two conditions:

1. Each individual probability P(X=x), where x is any value that the random variable can take, must be between 0 and 1, inclusive. That is, 0 ≤ P(X=x) ≤ 1.

2. The sum of all individual probabilities must be equal to 1. That is, Σ P(X=x) = 1, where the sum is over all possible values of X.

So, for your case, where X can take the values -1, 0, 4, 5, and 6, you need to find the probabilities P(X=-1), P(X=0), P(X=4), P(X=5), and P(X=6) such that each of these probabilities is between 0 and 1, and their sum is equal to 1.

Knowee AI · Accepted Answer

The question seems to be missing the table or the current probability values for the discrete random variable X. However, I can tell you the general rule for creating a legitimate probability distribution.

A legitimate probability distribution for a discrete random variable X must satisfy two conditions:

1. Each individual probability P(X=x), where x is any value that the random variable can take, must be between 0 and 1, inclusive. That is, 0 ≤ P(X=x) ≤ 1.

2. The sum of all individual probabilities must be equal to 1. That is, Σ P(X=x) = 1, where the sum is over all possible values of X.

So, for your case, where X can take the values -1, 0, 4, 5, and 6, you need to find the probabilities P(X=-1), P(X=0), P(X=4), P(X=5), and P(X=6) such that each of these probabilities is between 0 and 1, and their sum is equal to 1.

Which values are the best P(X=x) values to make this table a legitimate probability distribution for the discrete random variable X, whose possible values are -1, 0, 4, 5, and 6?

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