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The system of equations below has multiple solutions, all of which satisfy the equation 𝑦=43𝑥−2. If it can be determined, what is the value of a ? 8x-6y= 1212x-ay = 18

Question

The system of equations below has multiple solutions, all of which satisfy the equation 𝑦=43𝑥−2. If it can be determined, what is the value of a ? 8x-6y= 1212x-ay = 18

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Solution

To find the value of 'a', we first need to express the first equation in terms of y.

The first equation is 8x - 6y = 12.

We can rearrange this to find y in terms of x:

6y = 8x - 12 y = (8/6)x - 12/6 y = (4/3)x - 2

We know from the problem statement that y = 43x - 2.

So, we can set these two equations equal to each other:

(4/3)x - 2 = 43x - 2

Solving for x gives us x = 0.

Substituting x = 0 into the equation y = 43x - 2 gives us y = -2.

Now we can substitute x = 0 and y = -2 into the second equation to find the value of 'a':

12x - ay = 18 120 - a(-2) = 18 2a = 18 a = 18 / 2 a = 9

So, the value of 'a' is 9.

This problem has been solved

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