The magnitude of a vector is calculated using the formula:

Magnitude = sqrt(x^2 + y^2 + z^2)

Where x, y, and z are the components of the vector. In this case, for vector A = 3i + 2j + k, the components are x = 3, y = 2, and z = 1.

So, the magnitude of vector A is:

Magnitude = sqrt((3)^2 + (2)^2 + (1)^2)
Magnitude = sqrt(9 + 4 + 1)
Magnitude = sqrt(14)

So, the magnitude of vector A is √14, which is approximately 3.74.

Therefore, the closest answer is a. 3.7.

Question

The magnitude of a vector is calculated using the formula:

Magnitude = sqrt(x^2 + y^2 + z^2)

Where x, y, and z are the components of the vector. In this case, for vector A = 3i + 2j + k, the components are x = 3, y = 2, and z = 1.

So, the magnitude of vector A is:

Magnitude = sqrt((3)^2 + (2)^2 + (1)^2)
Magnitude = sqrt(9 + 4 + 1)
Magnitude = sqrt(14)

So, the magnitude of vector A is √14, which is approximately 3.74.

Therefore, the closest answer is a. 3.7.

Knowee AI · Accepted Answer

The magnitude of a vector is calculated using the formula:

Magnitude = sqrt(x^2 + y^2 + z^2)

Where x, y, and z are the components of the vector. In this case, for vector A = 3i + 2j + k, the components are x = 3, y = 2, and z = 1.

So, the magnitude of vector A is:

Magnitude = sqrt((3)^2 + (2)^2 + (1)^2)
Magnitude = sqrt(9 + 4 + 1)
Magnitude = sqrt(14)

So, the magnitude of vector A is √14, which is approximately 3.74.

Therefore, the closest answer is a. 3.7.

Find the magnitude of vector 𝐴 = 3𝑖 + 2𝑗 + 𝑘a. 3.7b. 13.0c. 14.0d. 6.6