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123456789#include <stdio.h> int main() { int count = 0; for (int i = 100; i >= 0; i -= 10) { count++; } printf("%d", count); return 0; }

Question

123456789#include <stdio.h> int main() { int count = 0; for (int i = 100; i >= 0; i -= 10) { count++; } printf("%d", count); return 0; }

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Solution

The given code is written in C language. It's a simple program that counts how many times a loop is executed. Here's a step-by-step explanation:

  1. The program starts with the inclusion of the standard input-output header file #include <stdio.h>. This is necessary for the program to use input-output functions like printf.

  2. The main function is declared. This is the entry point of the program.

  3. Inside the main function, an integer variable count is declared and initialized to 0. This variable is used to keep track of the number of times the loop is executed.

  4. A for loop is started with the initialization of variable i to 100. The condition for the loop is i >= 0, and in each iteration, i is decreased by 10.

  5. Inside the loop, count is incremented by 1 in each iteration. This means that count will hold the number of times the loop is executed.

  6. After the loop, the value of count is printed using the printf function.

  7. The main function returns 0, indicating that the program has ended successfully.

When this program is run, it will print the number 11. This is because the loop starts at 100 and decreases by 10 in each iteration until it reaches 0, so it runs 11 times in total (100, 90, 80, 70, 60, 50, 40, 30, 20, 10, 0).

This problem has been solved

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