123456789#include <stdio.h> int main() { int count = 0; for (int i = 100; i >= 0; i -= 10) { count++; } printf("%d", count); return 0; }
Question
123456789#include <stdio.h> int main() { int count = 0; for (int i = 100; i >= 0; i -= 10) { count++; } printf("%d", count); return 0; }
Solution
The given code is written in C language. It's a simple program that counts how many times a loop is executed. Here's a step-by-step explanation:
-
The program starts with the inclusion of the standard input-output header file
#include <stdio.h>. This is necessary for the program to use input-output functions likeprintf. -
The
mainfunction is declared. This is the entry point of the program. -
Inside the
mainfunction, an integer variablecountis declared and initialized to 0. This variable is used to keep track of the number of times the loop is executed. -
A
forloop is started with the initialization of variableito 100. The condition for the loop isi >= 0, and in each iteration,iis decreased by 10. -
Inside the loop,
countis incremented by 1 in each iteration. This means thatcountwill hold the number of times the loop is executed. -
After the loop, the value of
countis printed using theprintffunction. -
The
mainfunction returns 0, indicating that the program has ended successfully.
When this program is run, it will print the number 11. This is because the loop starts at 100 and decreases by 10 in each iteration until it reaches 0, so it runs 11 times in total (100, 90, 80, 70, 60, 50, 40, 30, 20, 10, 0).
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