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From a group of six people, two individuals are to be selected at random. How many possible selections are possible?Question 9Select one:a.36b.15c.8d.12

Question

From a group of six people, two individuals are to be selected at random. How many possible selections are possible?Question 9Select one:a.36b.15c.8d.12

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Solution

The answer to this question can be found using the combination formula, which is used when the order of selection does not matter. The formula is:

C(n, r) = n! / [r!(n-r)!]

where:

  • n is the total number of items,
  • r is the number of items to choose,
  • "!" denotes factorial, which means multiplying all positive integers up to that number.

In this case, n = 6 (the total number of people) and r = 2 (the number of people to be selected).

So,

C(6, 2) = 6! / [2!(6-2)!] = (654321) / [(21)(4321)] = (720) / (2*24) = 720 / 48 = 15

So, there are 15 possible selections. Therefore, the correct answer is b. 15.

This problem has been solved

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