A 2011 survey by the Bureau of Labor Statistics reported that 91% of Americans have paid leave. In January 2012, a random survey of 1,000 workers showed that 89% had paid leave.The resulting p-value is 0.0271; thus, the null hypothesis is rejected. It is concluded that there has been a decrease in the proportion of people who have paid leave from 2011 to January 2012.What type of error is possible in this situation?Group of answer choicesNeitherType IBothType II

In the 2010 General Social Survey, 17% of Americans said that they had no religious preference. In other words, they said they had “no religion” rather than being Protestant, Catholic, Jewish, or another religion. In 2014, the General Social Survey sampled 2,538 Americans and found that 21% of those surveyed said that they had no religious preference. The resulting p-value is 0.0003; thus, the null hypothesis is rejected. It is concluded that there has been an increase in the proportion of Americans who have no religious preference between 2010 and 2014.What type of error is possible in this situation?Group of answer choicesNeitherBothType IIType I

A manufacturer of rechargeable laptop batteries markets its batteries as having, on average, 500 charges. A consumer group decides to test this claim by assessing the number of times 30 of their laptop batteries can be recharged and finds the average is 497, with a standard deviation of 10.The resulting p-value is 0.1111; thus, the null hypothesis is not rejected. The consumer group concludes that the manufacturer’s claim that its laptop batteries can be recharged, on average, 500 times is accurate.What type of error is possible in this situation?Group of answer choicesType IIBothNeitherType I

If a school administrator claims that less than 50% of the students are dissatisfied with the food served in the school canteen. The claim used a sample data obtained from a survey of 500 students of the school wherein 54% indicated their dissatisfaction with the food served in the school canteen. Which of the following is the appropriate alternative hypothesis?p= 0.50p < 0.50p > 0.50p ≠ 0.50

Suppose that a major polling organization wanted to test the hypothesis that there was a change in the president’s “approval rating” since last month. Last month, 35% of the representative sample of registered voters approved of the president. For this month, the null hypothesis was that the approval rating equals 35% and the alternative hypothesis is that the approval rating does not equal 35%. The significance level for this test was 0.05.The results of the hypothesis test of the new survey showed a p-value of 0.008.Which of the following statements is correct? Check all that apply. The results were statistically significant. The results were not statistically significant. The null hypothesis should be rejected. The null hypothesis should be accepted. The null hypothesis cannot be rejected.

In each of the following examples, a test for the population proportion (p) is called for. You are asked to select the right null and alternative hypotheses.Scenario 1: The UCLA Internet Report (February 2003) estimated that roughly 8.7% of Internet users are extremely concerned about credit card fraud when buying online. Has that figure changed since? To test this, a random sample of 100 Internet users was chosen, and when interviewed, 10 said that they were extremely worried about credit card fraud when buying online. Let p be the proportion of all Internet users who are concerned about credit card fraud.The null hypothesis in this case is:H0: p = 8.7H0: p = 0.087H0: p = 0.10H0: p ≠ 0.087H0: p > 0.087The alternative hypothesis in this case is:Ha: p > 0.087Ha: p < 0.087Ha: p ≠ 0.087Ha: p = 0.087Reset this ActivityScenario 2: The UCLA Internet Report (February 2003) estimated that a proportion of roughly .75 of online homes are still using dial-up access, but claimed that the use of dial-up is declining. Is that really the case? To examine this, a follow-up study was conducted a year later in which out of a random sample of 1,308 households that had Internet access, 804 were connecting using a dial-up modem. Let p be the proportion of all U.S. Internet-using households that have dial-up access.The null hypothesis in this case is:H0: p = 0.75H0: p = 0.615H0: p < 0.75H0: p > 0.615The alternative hypothesis in this case is:Ha: p > 0.75Ha: p < 0.75Ha: p ≠ 0.75Ha: p < 0.615