A(g)⇌B(g)+C2( g) The correct relationship between KP,α and equilibrium pressure P is
Question
A(g)⇌B(g)+C2( g) The correct relationship between KP,α and equilibrium pressure P is
Solution
The given reaction is:
A(g) ⇌ B(g) + C2(g)
Let's assume the initial pressure of A is P and B and C2 are 0. At equilibrium, the pressure of A decreases by αP (where α is the degree of dissociation), and the pressures of B and C2 increase by αP and 2αP respectively.
According to the law of mass action, the equilibrium constant Kp for the reaction is given by:
Kp = (PB * PC2^2) / PA
Substituting the equilibrium pressures of A, B, and C2, we get:
Kp = [(αP) * (2αP)^2] / (P - αP)
Simplifying this, we get:
Kp = 4α^3P^2 / (1 - α)
So, the correct relationship between Kp, α, and equilibrium pressure P is Kp = 4α^3P^2 / (1 - α).
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