There are four pipes used to fill a tank at a constant rate. Altogether, the four pipes are able to fill up the tank in 4 hours. The owner wishes to reduce this time taken to 2 hours. How many more pipes filling up the tank at a constant rate will they need to install?123456

Three filling pipes, R, S and T, together, can fill an empty tank in two hours. S can fill the tank four times as fast as T. Initially, R alone is opened and after exactly x hours, it is closed and immediately S and T are opened together. The tank is full after exactly another y hours. If the tank was filled in a total of 4 hours, and x ≠ y, find the time (in hours) that T alone would take to fill the tank.6201224

A tank has four emptying taps, all of equal efficiencies, but each fixed at th, th, th and th of the height of the tank respectively. Two filling taps, each of which individually can fill the tank in 200 minutes, are also connected to the tank. If the ratio of the efficiency of each emptying tap and the efficiency of each filling tap is 1 : 3, and all the six taps are opened simultaneously, in how much time will the empty tank be filled?

There are two inlet pipes to a tank, one taking 8 minutes and the other taking 12 minutes to fill the tank. Find the capacity of the tank if for every second 5 gallons of water is pumped into the tank by the two taps.1) 1600 gallons                       2) 1440 gallons           3) 1200 gallons                       4) None

9 pipes are required to fill a tank in 4 hours. How long will it take if 12 pipes of the same type are used?Choices:-

A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?20 hours25 hours35 hoursCannot be determinedNone of these