A gas chamber of 100L consists of 60% oxygen and 40% nitrogen. Some amount of gas was removed from chamber and nitrogen was added such that the nitrogen % becomes 70.What amount of gas was removed?50L20L25L75L

To solve this problem, we can use the concept of the gas chamber's volume and the percentages of oxygen and nitrogen.

Step 1: Calculate the initial amount of oxygen and nitrogen in the gas chamber.

• The gas chamber has a volume of 100L.
• The initial percentage of oxygen is 60%, which means there are 60L of oxygen in the chamber (100L * 0.60).
• The initial percentage of nitrogen is 40%, which means there are 40L of nitrogen in the chamber (100L * 0.40).

Step 2: Calculate the final amount of nitrogen in the gas chamber.

• The desired percentage of nitrogen is 70%, which means there should be 70L of nitrogen in the chamber after the gas removal and addition.
• Since the initial amount of nitrogen was 40L, we need to add (70L - 40L) = 30L of nitrogen.

Step 3: Calculate the amount of gas that was removed.

• The total volume of the gas chamber remains the same at 100L.
• The initial amount of oxygen was 60L, and the final amount of nitrogen is 70L.
• Therefore, the amount of gas that was removed is (60L - 70L) = -10L.

Since the amount of gas removed cannot be negative, the correct answer is that no gas was removed from the chamber.