The capacitance of a passive capacitance transducer depends on the following factors, except?1 pointDistance between the two parallel platesThe area of the two parallel platesRelative dielectric constantThe mass of the two parallel plates

For a parallel plate capacitor, the capacitance 𝐶C is directly proportional to:a) The area of the platesb) The distance between the platesc) The square of the distance between the platesd) The volume between the plates

A variable dielectric capacitive displacement sensor consists of two square metal plates of5 cm in each side, separated by a 1 mm gap. A 1-mm-thick sheet of a dielectric material canalso slide between the two plates (same area as the plates). Given that the dielectric constant(i.e. relative permittivity) of air is 1 and that of the dielectric material is 4, for each case,calculate the capacitance of the sensor for the input displacements of x = 0.0, 2.5 and 5.0 cm.

The capacitance of a parallel plate capacitor with a dielectric medium

A parallel-plate capacitor has plates measuring 10cm×10cm, spaced 1 mm apart. The dielectric is mica with a relative permittivity of 5.0, and the permittivity of a vacuum is 8.85 ×10-12F/m. Which of these choices is closest to the actual capacitance value?Select one:a.5 pFb.50 pFc.500 pFd.5000 pF

find relationship between displacement and change in signal generated due to capacitive type transducer(proximity tutor). Explain and tell all the theory that can be used to create quiz out of this.