Four years ago, Victor purchased a very reliable automobile. His warranty has just expired, but the manufacturer has just offered him a 5-year, bumper-to-bumper warranty extension. The warranty costs $3,400. Victor constructs the following probability distribution with respect to anticipated costs if he chooses not to purchase the extended warranty. Cost (in $) 1,000 2,000 5,000 10,000 Probability 0.25 0.45 0.20 0.10
Question
Four years ago, Victor purchased a very reliable automobile. His warranty has just expired, but the manufacturer has just offered him a 5-year, bumper-to-bumper warranty extension. The warranty costs $3,400. Victor constructs the following probability distribution with respect to anticipated costs if he chooses not to purchase the extended warranty.
Cost (in $)
1,000
2,000
5,000
10,000
Probability
0.25
0.45
0.20
0.10
Solution
It seems like you want to know the expected cost if Victor chooses not to purchase the extended warranty.
The expected value (E) of a probability distribution is calculated by multiplying each outcome by its probability and then summing these products.
So, for Victor's situation, the expected cost (E) would be calculated as follows:
E = (1,000 * 0.25) + (2,000 * 0.45) + (5,000 * 0.20) + (10,000 * 0.10)
E = 250 + 900 + 1000 + 1000
E = $3,150
So, the expected cost if Victor chooses not to purchase the extended warranty is $3,150. This is less than the cost of the extended warranty, so based on this analysis, it would not be worth it for Victor to purchase the extended warranty. However, this decision also depends on Victor's risk tolerance and other factors not included in this analysis.
Similar Questions
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