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Rahul steals 4 mangoes for every dozen whenever he purchases them from a farmer and his customers steal 2 mangoes for every dozen whenever they purchase the mangoes from Rahul. What is the profit or loss percentage of Rahul, if he marks a dozen at 25% above the price that is offered by the farmer and offers a discount of 9%?

Question

Rahul steals 4 mangoes for every dozen whenever he purchases them from a farmer and his customers steal 2 mangoes for every dozen whenever they purchase the mangoes from Rahul. What is the profit or loss percentage of Rahul, if he marks a dozen at 25% above the price that is offered by the farmer and offers a discount of 9%?

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Solution

Let's break down the problem step by step:

Step 1: Let's assume the cost price of a dozen mangoes for Rahul is $100.

Step 2: Rahul steals 4 mangoes for every dozen he purchases. So, he gets 16 mangoes for 100.ThecostpriceofeachmangoforRahulis100. The cost price of each mango for Rahul is 100/16 = $6.25.

Step 3: Rahul sells these mangoes at 25% above the cost price. So, the selling price of each mango for Rahul is 6.25+256.25 + 25% of 6.25 = $7.81 approximately.

Step 4: Rahul offers a discount of 9% on the selling price. So, the final selling price of each mango for Rahul is 7.8197.81 - 9% of 7.81 = $7.11 approximately.

Step 5: Rahul's customers steal 2 mangoes for every dozen they purchase. So, they get 14 mangoes for the price of 12. The selling price of a dozen mangoes for Rahul's customers is 12 * 7.11=7.11 = 85.32.

Step 6: The cost price of a dozen mangoes for Rahul's customers is 14 * 6.25=6.25 = 87.5.

Step 7: To find the profit or loss percentage, we use the formula: [(Selling Price - Cost Price) / Cost Price] * 100. Substituting the values, we get [(85.32 - 87.5) / 87.5] * 100 = -2.48%.

So, Rahul incurs a loss of 2.48%.

This problem has been solved

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