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Use the fact that matrices A and B are row-equivalent.A = −2 −5 8 0 −17 1 3 −5 1 5−5 −9 13 7 −671 7 −13 5 −3B = 1 0 1 0 1 0 1 −2 0 30 0 0 1 −50 0 0 0 0(a) Find the rank and nullity of A.rank nullity

Question

Use the fact that matrices A and B are row-equivalent.A = −2 −5 8 0 −17 1 3 −5 1 5−5 −9 13 7 −671 7 −13 5 −3B = 1 0 1 0 1 0 1 −2 0 30 0 0 1 −50 0 0 0 0(a) Find the rank and nullity of A.rank nullity

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Solution

The rank of a matrix is the maximum number of linearly independent rows or columns. The nullity of a matrix is the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0.

Step 1: Find the rank of A To find the rank of A, we need to transform it to its row echelon form or reduced row echelon form. However, since A and B are row-equivalent, they have the same rank. Looking at matrix B, we can see that it has 3 non-zero rows. Therefore, the rank of A is 3.

Step 2: Find the nullity of A The nullity of a matrix is given by the formula nullity = n - rank, where n is the number of columns in the matrix. Matrix A has 5 columns and its rank is 3. Therefore, the nullity of A is 5 - 3 = 2.

So, the rank of A is 3 and the nullity of A is 2.

This problem has been solved

Similar Questions

Use the fact that matrices A and B are row-equivalent.A = −2 −5 8 0 −17 1 3 −5 1 5−5 −9 13 7 −671 7 −13 5 −3B = 1 0 1 0 1 0 1 −2 0 30 0 0 1 −50 0 0 0 0(a) Find the rank and nullity of A.rank nullity     (b) Find a basis for the nullspace of A. (c) Find a basis for the row space of A. (d) Find a basis for the column space of A. (e) Determine whether or not the rows of A are linearly independent.independentdependent    (f) Let the columns of A be denoted by a1, a2, a3, a4, and a5. Which of the following sets is (are) linearly independent? (Select all that apply.){a1, a2, a4}{a1, a2, a3}{a1, a3, a5}

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Use the fact that matrices A and B are row-equivalent.A = −2 −5 8 0 −17 1 3 −5 1 5−5 −9 13 7 −671 7 −13 5 −3B = 1 0 1 0 1 0 1 −2 0 30 0 0 1 −50 0 0 0 0

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