If the average of m numbers is n2 and that of n numbers is m2, find the average of (m+n) numbersnmm2nmnn2m

The question seems to be a bit jumbled, but I'll try to interpret it as best as I can.

If the average of m numbers is n^2, the sum of those m numbers is m*n^2.

Similarly, if the average of n numbers is m^2, the sum of those n numbers is n*m^2.

The sum of all m+n numbers is therefore mn^2 + nm^2.

To find the average of these m+n numbers, we divide the total sum by the number of terms, which is m+n.

So, the average of the m+n numbers is (mn^2 + nm^2) / (m+n).

The question seems to be a bit jumbled, but I'll try to interpret it as best as I can.

If the average of m numbers is n^2, then the sum of those m numbers is m*n^2.

Similarly, if the average of n numbers is m^2, then the sum of those n numbers is n*m^2.

To find the average of the (m+n) numbers, we would add up the sum of the m numbers and the n numbers, and then divide by (m+n).

So, the sum of the m numbers and n numbers is mn^2 + nm^2.

Therefore, the average of the (m+n) numbers is (mn^2 + nm^2) / (m+n).

The question seems to be a bit jumbled, but I'll try to interpret it as best as I can.

Given that the average of m numbers is n^2 and the average of n numbers is m^2, we are asked to find the average of (m+n) numbers.

Step 1: Understand the problem The average of a set of numbers is the sum of the numbers divided by the count of the numbers. So, the sum of m numbers is mn^2 and the sum of n numbers is nm^2.

Step 2: Find the sum of (m+n) numbers The sum of (m+n) numbers is the sum of m numbers plus the sum of n numbers, which is mn^2 + nm^2.

Step 3: Find the average of (m+n) numbers The average of (m+n) numbers is the sum of (m+n) numbers divided by the count of the numbers, which is (mn^2 + nm^2) / (m+n).

So, the average of (m+n) numbers is (mn^2 + nm^2) / (m+n).