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Solve the equation for all real solutions in simplest form.m, squared, plus, 11, m, plus, 16, equals, 0m 2 +11m+16=0

Question

Solve the equation for all real solutions in simplest form.m, squared, plus, 11, m, plus, 16, equals, 0m 2 +11m+16=0

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Solution

To solve the quadratic equation m^2 + 11m + 16 = 0, we can use the quadratic formula, which is m = [-b ± sqrt(b^2 - 4ac)] / (2a). In this equation, a = 1, b = 11, and c = 16.

Step 1: Calculate the discriminant, which is b^2 - 4ac. Discriminant = (11)^2 - 4116 = 121 - 64 = 57.

Step 2: Substitute a, b, and the discriminant into the quadratic formula. m = [-11 ± sqrt(57)] / (2*1) m = [-11 ± sqrt(57)] / 2

So, the solutions of the equation m^2 + 11m + 16 = 0 are m = [-11 + sqrt(57)] / 2 and m = [-11 - sqrt(57)] / 2.

This problem has been solved

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