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A is thrice as efficient as B and takes 10 days less than B takes to do the same work. In howmany days, B alone can finish the whole work?

Question

A is thrice as efficient as B and takes 10 days less than B takes to do the same work. In howmany days, B alone can finish the whole work?

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Solution

Let's assume that B takes x days to finish the whole work.

According to the given information, A is thrice as efficient as B. This means that A can finish the same amount of work in one-third of the time taken by B. So, A takes x/3 days to finish the whole work.

It is also given that A takes 10 days less than B to do the same work. This means that A takes x - 10 days to finish the whole work.

Since we know that A takes x/3 days and x - 10 days to finish the whole work, we can set up the equation:

x/3 = x - 10

To solve this equation, we can multiply both sides by 3 to eliminate the fraction:

3(x/3) = 3(x - 10) x = 3x - 30

Next, we can simplify the equation:

2x = 30 x = 15

Therefore, B alone can finish the whole work in 15 days.

This problem has been solved

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