A survey was conducted in five countries. The percentages of respondents whose household members own more than one personal computer, laptop, notebook or iPad are as follows:AustraliaNew ZealandChinaJapanSouth Korea53%48%38%54%49%Suppose that the survey was based on 500 respondents in each country.a) At the 0.05 level of significance, determine whether there is some significant difference in the proportion of households in these countries who own more than one computer (personal computer, laptop, notebook or iPad). Do the calculations first manually and then in R.b) Find the approximate p-value of the test in (a) from the relevant statistical table.

A survey was conducted in five countries. The percentages of respondents whose household members own more than one personal computer, laptop, notebook or iPad are as follows:AustraliaNew ZealandChinaJapanSouth Korea53%48%38%54%49%Suppose that the survey was based on 500 respondents in each country.a) At the 0.05 level of significance, determine whether there is some significant difference in the proportion of households in these countries who own more than one computer (personal computer, laptop, notebook or iPad). Do the calculations first manually and then in R.

The following two hypotheses are tested:Ho: The proportion of U.S. adults who oppose same-sex marriage is roughly 50%.Ha: The proportion of U.S. adults who oppose same-sex marriage is above 50% (i.e., the majority oppose).Suppose a survey was conducted in which a random sample of 1,100 U.S. adults was asked about their opinions about same-sex marriage, and based on the data, the p-value was found to be .002.Use a .05 (5%) significance level.The fact that the p-value = .002 means that

Your study is only valid if your p-value is < 0.05.Group of answer choicesTrueFalse

7.Suppose the population proportion is 0.200.20 . If the sample size is equal to 5050 , what is the approximate sampling distribution of the sample proportion, P̂ 𝑃^ ?Multiple choice 5 Question 3  N(0.20,0.16)𝑁(0.20,0.16)   N(0.20,0.0032)𝑁(0.20,0.0032)   N(0.20,0.057)𝑁(0.20,0.057)   N(0.80,0.16)𝑁(0.80,0.16)

In each of the following examples, a test for the population proportion (p) is called for. You are asked to select the right null and alternative hypotheses.Scenario 1: The UCLA Internet Report (February 2003) estimated that roughly 8.7% of Internet users are extremely concerned about credit card fraud when buying online. Has that figure changed since? To test this, a random sample of 100 Internet users was chosen, and when interviewed, 10 said that they were extremely worried about credit card fraud when buying online. Let p be the proportion of all Internet users who are concerned about credit card fraud.The null hypothesis in this case is:H0: p = 8.7H0: p = 0.087H0: p = 0.10H0: p ≠ 0.087H0: p > 0.087The alternative hypothesis in this case is:Ha: p > 0.087Ha: p < 0.087Ha: p ≠ 0.087Ha: p = 0.087Reset this ActivityScenario 2: The UCLA Internet Report (February 2003) estimated that a proportion of roughly .75 of online homes are still using dial-up access, but claimed that the use of dial-up is declining. Is that really the case? To examine this, a follow-up study was conducted a year later in which out of a random sample of 1,308 households that had Internet access, 804 were connecting using a dial-up modem. Let p be the proportion of all U.S. Internet-using households that have dial-up access.The null hypothesis in this case is:H0: p = 0.75H0: p = 0.615H0: p < 0.75H0: p > 0.615The alternative hypothesis in this case is:Ha: p > 0.75Ha: p < 0.75Ha: p ≠ 0.75Ha: p < 0.615