Knowee
Questions
Features
Study Tools

The new furniture for the English Department's Writer's Lounge has just arrived and is down at the loading dock. A 200-Newton force is used to pull a 35.7-kg furniture crate up the loading dock to a height of 3.87 meters at a constant speed. Determine the increase in potential energy of the crate.

Question

The new furniture for the English Department's Writer's Lounge has just arrived and is down at the loading dock. A 200-Newton force is used to pull a 35.7-kg furniture crate up the loading dock to a height of 3.87 meters at a constant speed. Determine the increase in potential energy of the crate.

🧐 Not the exact question you are looking for?Go ask a question

Solution

The increase in potential energy of the crate can be calculated using the formula for gravitational potential energy:

PE = m * g * h

where: PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height the object is lifted.

Given: m = 35.7 kg, g = 9.8 m/s² (approximate value on the surface of the Earth), and h = 3.87 m,

we can substitute these values into the formula:

PE = 35.7 kg * 9.8 m/s² * 3.87 m = 1357.626 Joules

So, the increase in potential energy of the crate is approximately 1357.626 Joules.

This problem has been solved

Similar Questions

Question 15SavedA forklift raises a crate 300 cm into the air. The mass of the crate is 1800 kg.Calculate the gravitational potential energy given to the crate. Give the answer in joules and show your working out.

A crane lifts a container 48 m vertically upwards. The mass of the container is 30 000 kg.Calculate the energy transferred to the gravitational potential energy stored in the container.

4. A crate is pulled up a ramp a distance of 20 m with a force of F = [800, 500]. The crate ends up 2 m higher above the ground than where it started.

A worker pushing a 35.0 kg wooden crate at a constant speed for 12.0 m along a woodfloor does 350 J of work by applying a constant horizontal force of magnitudeF on the crate.(a) Determine the value of F.(b) If the worker now applies a force greater than F, describe the subsequent motion ofthe crate.(c) Describe what would happen to the crate if the applied force is less than F.

A box of mass 200 kg is moving in the x-direction with a constant speed of 40 m/s. Aretarding force F = − 20x J/m moves it from x = 10 m to x = 20 m. Estimate its finalkinetic energy.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.