Find the derivative of the y=ln(11x+41)๐ฆ=๐๐(11๐ฅ+41)Question 1Answera. ๐๐ฆ๐๐ฅ=11(11๐ฅ+41)b. ๐๐ฆ๐๐ฅ=11(๐ฅ+41)c. ๐๐ฆ๐๐ฅ=41(๐ฅ+41)d. ๐๐ฆ๐๐ฅ=41(11๐ฅ+41)e.
Question
Find the derivative of the y=ln(11x+41)๐ฆ=๐๐(11๐ฅ+41)Question 1Answera. ๐๐ฆ๐๐ฅ=11(11๐ฅ+41)b. ๐๐ฆ๐๐ฅ=11(๐ฅ+41)c. ๐๐ฆ๐๐ฅ=41(๐ฅ+41)d. ๐๐ฆ๐๐ฅ=41(11๐ฅ+41)e.
Solution
The derivative of y=ln(11x+41) can be found using the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.
Step 1: Identify the outer and inner functions. Here, the outer function is ln(x) and the inner function is 11x+41.
Step 2: Find the derivative of the outer function. The derivative of ln(x) is 1/x.
Step 3: Find the derivative of the inner function. The derivative of 11x+41 is 11.
Step 4: Apply the chain rule. According to the chain rule, the derivative of y=ln(11x+41) is (1/(11x+41)) * 11.
So, the derivative of y=ln(11x+41) is 11/(11x+41). This corresponds to option a. ๐๐ฆ๐๐ฅ=11/(11๐ฅ+41).
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