The length of a rectangle is 2 ft longer than its width.If the perimeter of the rectangle is 68 ft, find its length and width.

Sure, let's solve this step by step.

Step 1: Let's denote the width of the rectangle as x (in feet). Therefore, the length of the rectangle is x + 2 (since it's given that the length is 2 ft longer than the width).

Step 2: The formula for the perimeter of a rectangle is 2*(length + width). In this case, it's given that the perimeter is 68 ft. So, we can set up the equation as follows: 2*(x + (x + 2)) = 68.

Step 3: Simplify the equation. This gives us 2*(2x + 2) = 68.

Step 4: Distribute the 2 on the left side of the equation. This gives us 4x + 4 = 68.

Step 5: Subtract 4 from both sides of the equation to isolate the term with x. This gives us 4x = 64.

Step 6: Divide both sides of the equation by 4 to solve for x. This gives us x = 16.

So, the width of the rectangle is 16 ft and the length of the rectangle is 16 + 2 = 18 ft.