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ou have a list arr of all integers in the range [1, n] sorted in a strictly increasing order. Apply the following algorithm on arr:Starting from left to right, remove the first number and every other number afterward until you reach the end of the list.Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers.Keep repeating the steps again, alternating left to right and right to left, until a single number remains.Given the integer n, return the last number that remains in arr.Example 1:Input:n = 9Output:6Explanation:arr = [1, 2,3, 4,5, 6,7, 8,9] arr = [2,4, 6,8] arr = [2, 6] arr = [6]Example 2:Input:n = 1Output:1Constraints:- 1 <= n <= 109

Question

ou have a list arr of all integers in the range [1, n] sorted in a strictly increasing order. Apply the following algorithm on arr:Starting from left to right, remove the first number and every other number afterward until you reach the end of the list.Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers.Keep repeating the steps again, alternating left to right and right to left, until a single number remains.Given the integer n, return the last number that remains in arr.Example 1:Input:n = 9Output:6Explanation:arr = [1, 2,3, 4,5, 6,7, 8,9] arr = [2,4, 6,8] arr = [2, 6] arr = [6]Example 2:Input:n = 1Output:1Constraints:- 1 <= n <= 109

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Solution

The problem is asking to return the last number that remains after applying a certain algorithm on a list of integers from 1 to n. The algorithm is as follows:

  1. Starting from left to right, remove the first number and every other number afterward until you reach the end of the list.
  2. Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers.
  3. Keep repeating the steps again, alternating left to right and right to left, until a single number remains.

Here is a Python solution using a deque:

from collections import deque

def lastRemaining(n):
    d = deque(range(1, n+1))
    left = True

    while len(d) > 1:
        if left:
            d.popleft()
        else:
            d.pop()
        d.rotate(-1 if left else 1)
        left = not left

    return d[0]

In this solution, we use a deque to efficiently remove elements from both ends of the list. We start by initializing a deque with all integers from 1 to n. Then, we use a boolean variable left to keep track of the direction. If left is True, we remove the first element of the deque, otherwise we remove the last element. After removing an element, we rotate the deque to the left if the current direction is left, and to the right otherwise. Finally, we flip the direction and repeat the process until only one element remains in the deque, which is the result.

This problem has been solved

Similar Questions

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