An RLC circuit has a 88.0 Ω resistor, a 8.80 mH inductor and a 498 nF capacitor. What is the peak current if the voltage source oscillates with a peak voltage of 9.50 V, with a frequency of 4.81×103 Hz?Magnitude:

To find the peak current in an RLC circuit, we first need to find the impedance (Z) of the circuit. The impedance of an RLC circuit is given by the formula:

Z = sqrt(R^2 + (XL - XC)^2)

where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

The inductive reactance (XL) is given by the formula:

XL = 2πfL

where f is the frequency and L is the inductance.

The capacitive reactance (XC) is given by the formula:

XC = 1/(2πfC)

where f is the frequency and C is the capacitance.

First, let's calculate XL and XC:

XL = 2π * 4.81×10^3 Hz * 8.80×10^-3 H = 135.3 Ω

XC = 1/(2π * 4.81×10^3 Hz * 498×10^-9 F) = 66.5 Ω

Now, we can calculate the impedance:

Z = sqrt((88.0 Ω)^2 + (135.3 Ω - 66.5 Ω)^2) = 111.8 Ω

The peak current (I) is given by the formula:

I = V/Z

where V is the peak voltage.

So, the peak current is:

I = 9.50 V / 111.8 Ω = 0.085 A or 85 mA.

To find the peak current in an RLC circuit, we first need to find the impedance (Z) of the circuit. The impedance of an RLC circuit is given by the formula:

Z = sqrt(R^2 + (XL - XC)^2)

where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

The inductive reactance (XL) is given by the formula:

XL = 2πfL

where f is the frequency and L is the inductance.

The capacitive reactance (XC) is given by the formula:

XC = 1/(2πfC)

where f is the frequency and C is the capacitance.

First, let's calculate XL and XC:

XL = 2π * 4.81×10^3 Hz * 8.80×10^-3 H = 135.3 Ω

XC = 1/(2π * 4.81×10^3 Hz * 498×10^-9 F) = 66.5 Ω

Now, we can calculate the impedance:

Z = sqrt((88.0 Ω)^2 + (135.3 Ω - 66.5 Ω)^2) = 111.8 Ω

Finally, we can find the peak current (I) using Ohm's law:

I = V/Z

I = 9.50 V / 111.8 Ω = 0.085 A or 85 mA

So, the peak current in the circuit is 85 mA.

To find the peak current in an RLC circuit, we first need to find the impedance (Z) of the circuit. The impedance of an RLC circuit is given by the formula:

Z = sqrt(R^2 + (XL - XC)^2)

where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.

The inductive reactance (XL) is given by the formula:

XL = 2πfL

where f is the frequency and L is the inductance.

The capacitive reactance (XC) is given by the formula:

XC = 1/(2πfC)

where f is the frequency and C is the capacitance.

First, let's calculate XL and XC:

XL = 2π * 4.81×10^3 Hz * 8.80×10^-3 H = 135.3 Ω

XC = 1/(2π * 4.81×10^3 Hz * 498×10^-9 F) = 66.5 Ω

Now, we can calculate the impedance:

Z = sqrt((88.0 Ω)^2 + (135.3 Ω - 66.5 Ω)^2) = 111.8 Ω

Finally, we can find the peak current (I) using Ohm's law:

I = V/Z

I = 9.50 V / 111.8 Ω = 0.085 A or 85 mA

So, the peak current in the circuit is 85 mA.