What is the cut off frequency for an RL series circuit if R = 1500 ohm and L = 100 mH?Group of answer choices238.9 Hz239 Hz0.234 Hz2389 Hz
Question
What is the cut off frequency for an RL series circuit if R = 1500 ohm and L = 100 mH?Group of answer choices238.9 Hz239 Hz0.234 Hz2389 Hz
Solution
The cut-off frequency (f) for an RL series circuit can be calculated using the formula:
f = R / (2 * π * L)
Where: R = Resistance (in ohms) L = Inductance (in henries)
Given: R = 1500 ohms L = 100 mH = 0.1 H (since 1H = 1000 mH)
Substituting these values into the formula, we get:
f = 1500 / (2 * π * 0.1) f = 1500 / (0.2 * π) f = 2387.32 Hz
So, the cut-off frequency is approximately 2387.32 Hz. However, if we round it to the nearest whole number, it becomes 2387 Hz. None of the options provided exactly match this result, but 2389 Hz is the closest one.
Similar Questions
What is the cut off frequency for an RC series circuit if R = 1500 ohm and C = 100 nF?Group of answer choices314 Hz1.062 Hz942 μHz1062 Hz
A filter consist of resistance = 25k Ohm. and capacitance = 220 pF. Find out the cut of frequency.
A filter consist of resistance = 10k Ohm. and capacitance = 220 pF. Find out the cut of frequency.72.34 KHz7.234 KHz7.234 MHz72.34 Hz
The above figure exhibit the response of the band pass filter. fL = Lower cut off frequency = 100 HzfH = Higher cut off frequency = 10K HzGain at the fH is 15 dBWhat will be the Q factor of the filter?999.91811
In the above BPF circuit, the desire higher cut off frequency (fh) = 6 KHz. R1=R3=1 K Ohm. and R5=R6 = 10K Ohm. R2 = 10 k Ohm and R4 = 1K Ohm . Find out the value of the capacitor C2 .
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.