During bromination of bromobenzene, why is the sigma complex formed from ortho attack or para attack more stable than the sigma complex formed from meta attack?Select answer from the options belowThe ortho-para attack has an additional structure in the sigma complex that the meta attack complex does not have which adds to the stability.The additional structure in the ortho-para attack sigma complex increases the influence of resonance which is the strongest force, stabilizing it.The resonance forces are stronger than the inductive forces, raising the energy of activation and therefore stability of the ortho-para attack in order to overcome it.The meta attack sigma complex has a lower energy of activation from the lack of a fourth complex, destabilizing it.Save for LaterSubmit Answer

During nitration of chlorobenzene, the sigma complex formed from ortho attack or para attack will have additional stability relative to the sigma complex formed from meta attack.Select answer from the options belowTrueFalse

For the nitration or bromination of anisole, why is the meta product only obtained in minimal amounts?Select answer from the options belowThe intermediate sigma complex formed has the lowest energy and therefore the lowest energy of activation.The intermediate sigma complex formed has the highest energy and therefore the largest energy of activation.The intermediate sigma complex formed has the fewest configurations and therefore is the lowest in energy.The intermediate sigma complex formed has the most configurations and therefore is the highest in energy.

For the nitration or bromination of anisole, why is the meta product only obtained in minimal amounts?Select answer from the options belowThe intermediate sigma complex formed has the fewest configurations and therefore is the lowest in energy.The intermediate sigma complex formed has the highest energy and therefore the largest energy of activation.The intermediate sigma complex formed has the most configurations and therefore is the highest in energy.The intermediate sigma complex formed has the lowest energy and therefore the lowest energy of activation.

One resonance structure of the bromate ion is shown below.  What is the bond order of the bromine–oxygen bonds in BrO3—?

Sigma bond is stronger than pi bond. Give reason.