Using the discriminant, determine the number of solutions for the quadratic equation 2x2+5x+1=02𝑥2+5𝑥+1=0.Δ=Δ= ∴∴ there is/are solution(s)
Question
Using the discriminant, determine the number of solutions for the quadratic equation 2x2+5x+1=02𝑥2+5𝑥+1=0.Δ=Δ= ∴∴ there is/are solution(s)
Solution
The discriminant of a quadratic equation is given by the formula Δ = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
In the given equation 2x² + 5x + 1 = 0, a = 2, b = 5, and c = 1.
Substituting these values into the formula, we get:
Δ = (5)² - 4*(2)*(1) Δ = 25 - 8 Δ = 17
Since the discriminant is greater than 0, the quadratic equation has two distinct real solutions.
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