To find the force exerted on one face by the water pressure, we need to calculate the pressure at the center of mass of the plate and then multiply it by the area of the plate.

1. First, we need to find the depth of the center of mass of the plate. Since the plate is rectangular and submerged vertically, the center of mass will be at the average of the greatest and least depths. So, the depth (h) is (1.50m + 0.60m) / 2 = 1.05m.

2. Next, we calculate the pressure at the center of mass using the formula P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. Substituting the given values, we get P = 1025kg/m^3 * 9.81m/s^2 * 1.05m = 10561.0125 Pa.

3. Finally, we find the force exerted on the plate by multiplying the pressure by the area of the plate. The area (A) is 1.5m * 0.5m = 0.75m^2. So, the force (F) is P * A = 10561.0125 Pa * 0.75 m^2 = 7920.759375 N.

So, the force exerted on one face of the plate by the water pressure is approximately 7921 N.

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To find the force exerted on one face by the water pressure, we need to calculate the pressure at the center of mass of the plate and then multiply it by the area of the plate.

1. First, we need to find the depth of the center of mass of the plate. Since the plate is rectangular and submerged vertically, the center of mass will be at the average of the greatest and least depths. So, the depth (h) is (1.50m + 0.60m) / 2 = 1.05m.

2. Next, we calculate the pressure at the center of mass using the formula P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. Substituting the given values, we get P = 1025kg/m^3 * 9.81m/s^2 * 1.05m = 10561.0125 Pa.

3. Finally, we find the force exerted on the plate by multiplying the pressure by the area of the plate. The area (A) is 1.5m * 0.5m = 0.75m^2. So, the force (F) is P * A = 10561.0125 Pa * 0.75 m^2 = 7920.759375 N.

So, the force exerted on one face of the plate by the water pressure is approximately 7921 N.

Knowee AI · Accepted Answer

To find the force exerted on one face by the water pressure, we need to calculate the pressure at the center of mass of the plate and then multiply it by the area of the plate.

1. First, we need to find the depth of the center of mass of the plate. Since the plate is rectangular and submerged vertically, the center of mass will be at the average of the greatest and least depths. So, the depth (h) is (1.50m + 0.60m) / 2 = 1.05m.

2. Next, we calculate the pressure at the center of mass using the formula P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. Substituting the given values, we get P = 1025kg/m^3 * 9.81m/s^2 * 1.05m = 10561.0125 Pa.

3. Finally, we find the force exerted on the plate by multiplying the pressure by the area of the plate. The area (A) is 1.5m * 0.5m = 0.75m^2. So, the force (F) is P * A = 10561.0125 Pa * 0.75 m^2 = 7920.759375 N.

So, the force exerted on one face of the plate by the water pressure is approximately 7921 N.

Rat rectangular plate, dimension 1.5m length by 0.5m width is immersed inkaline water (density 1025kg / (m ^ 3) ) such that their greatest and least depths are 1.50m and 0.60m respectively. Determine the force exerted on one face by the water pressure.

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