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Let F be the conservative vector fieldF(x, y) = (x2 + xy2, y2 + x2y)and let C be the circle x2 + y2 = 2 of radius √2 centred at (0, 0).(a) Find a scalar potential function ϕ for F that satisfies ϕ(0, 0) = 0.(b) Use the method of Lagrange multipliers to find the maximum and minimum of ϕ from(a) on C

Question

Let F be the conservative vector fieldF(x, y) = (x2 + xy2, y2 + x2y)and let C be the circle x2 + y2 = 2 of radius √2 centred at (0, 0).(a) Find a scalar potential function ϕ for F that satisfies ϕ(0, 0) = 0.(b) Use the method of Lagrange multipliers to find the maximum and minimum of ϕ from(a) on C

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Solution

(a) A scalar potential function ϕ for F can be found by integrating the components of F.

The x-component of F is x^2 + xy^2, and the y-component is y^2 + x^2y.

We integrate the x-component with respect to x and the y-component with respect to y:

∫(x^2 + xy^2) dx = (1/3)x^3 + (1/2)x^2y^2 + g(y)

∫(y^2 + x^2y) dy = (1/3)y^3 + (1/2)x^2y^2 + h(x)

Comparing these two expressions, we can see that g(y) must be equal to (1/3)y^3 and h(x) must be equal to (1/3)x^3.

Therefore, a scalar potential function ϕ for F that satisfies ϕ(0, 0) = 0 is:

ϕ(x, y) = (1/3)x^3 + (1/2)x^2y^2 + (1/3)y^3

(b) To find the maximum and minimum of ϕ on C using the method of Lagrange multipliers, we need to solve the following system of equations:

∇ϕ = λ∇g

where g(x, y) = x^2 + y^2 - 2 (the equation for C), and λ is the Lagrange multiplier.

The gradient of ϕ is ∇ϕ = (x^2 + xy^2, 2xy + y^2) and the gradient of g is ∇g = (2x, 2y).

Setting ∇ϕ = λ∇g gives us the following system of equations:

x^2 + xy^2 = λ2x 2xy + y^2 = λ2y

Solving this system of equations will give us the values of x and y that maximize and minimize ϕ on C.

This problem has been solved

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