If a body floats completely submerged in water then buoyant force is

If a body is completely submerged in water, the buoyant force on it is equal to the weight of the water displaced by it. This is according to Archimedes' principle which states that "Any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of the fluid displaced by the object."

Here are the steps to calculate it:

1. Determine the volume of the object. This can be done by measuring the dimensions of the object and using the appropriate formula for its shape. For example, the volume of a cube is the length of one side cubed.

2. Calculate the volume of water displaced by the object. Since the object is completely submerged, the volume of water displaced is equal to the volume of the object.

3. Determine the density of the water. This is typically 1 gram per cubic centimeter (g/cm^3) or 1,000 kilograms per cubic meter (kg/m^3).

4. Calculate the weight of the water displaced. This is done by multiplying the volume of the water displaced by the density of the water and then by the acceleration due to gravity (approximately 9.8 m/s^2).

The result is the buoyant force on the object. If the weight of the object is less than the buoyant force, the object will float. If the weight of the object is greater than the buoyant force, the object will sink. If the weight of the object is equal to the buoyant force, the object will remain submerged in the water without sinking or floating.