The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 3)² + 41, we can see that a = 1, h = 3, and k = 41.

To convert this into the standard form, we expand the equation:

x = (y - 3)² + 41
x = y² - 6y + 9 + 41
x = y² - 6y + 50

So, the standard form of the equation is x = y² - 6y + 50.

Question

The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 3)² + 41, we can see that a = 1, h = 3, and k = 41.

To convert this into the standard form, we expand the equation:

x = (y - 3)² + 41
x = y² - 6y + 9 + 41
x = y² - 6y + 50

So, the standard form of the equation is x = y² - 6y + 50.

Knowee AI · Accepted Answer

The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 3)² + 41, we can see that a = 1, h = 3, and k = 41.

To convert this into the standard form, we expand the equation:

x = (y - 3)² + 41
x = y² - 6y + 9 + 41
x = y² - 6y + 50

So, the standard form of the equation is x = y² - 6y + 50.

The vertex form of the equation of a parabola is x = (y - 3)2 + 41.What is the standard form of the equation?