To find the grams of Calcium Carbonate (CaCO3) in the 3L water sample with a hardness of 300ppm by mass CaCO3, we can use the following steps:

Step 1: Convert the ppm (parts per million) to a mass ratio.
Since 1 ppm is equivalent to 1 mg/L, we can convert 300 ppm to 300 mg/L.

Step 2: Convert the mg/L to grams.
Since 1 L of water has a mass of 1000 grams, we can convert 300 mg/L to grams by dividing it by 1000.
300 mg/L = 0.3 g/L

Step 3: Multiply the grams per liter by the volume of the water sample.
Since we have a 3L water sample, we can multiply 0.3 g/L by 3 to find the total grams of CaCO3.
0.3 g/L * 3 L = 0.9 g

Therefore, the grams of Calcium Carbonate (CaCO3) in the 3L water sample is 0.9g.

So, the correct answer is option c. 0.30g.

Question

To find the grams of Calcium Carbonate (CaCO3) in the 3L water sample with a hardness of 300ppm by mass CaCO3, we can use the following steps:

Step 1: Convert the ppm (parts per million) to a mass ratio.
Since 1 ppm is equivalent to 1 mg/L, we can convert 300 ppm to 300 mg/L.

Step 2: Convert the mg/L to grams.
Since 1 L of water has a mass of 1000 grams, we can convert 300 mg/L to grams by dividing it by 1000.
300 mg/L = 0.3 g/L

Step 3: Multiply the grams per liter by the volume of the water sample.
Since we have a 3L water sample, we can multiply 0.3 g/L by 3 to find the total grams of CaCO3.
0.3 g/L * 3 L = 0.9 g

Therefore, the grams of Calcium Carbonate (CaCO3) in the 3L water sample is 0.9g.

So, the correct answer is option c. 0.30g.

Knowee AI · Accepted Answer

To find the grams of Calcium Carbonate (CaCO3) in the 3L water sample with a hardness of 300ppm by mass CaCO3, we can use the following steps:

Step 1: Convert the ppm (parts per million) to a mass ratio.
Since 1 ppm is equivalent to 1 mg/L, we can convert 300 ppm to 300 mg/L.

Step 2: Convert the mg/L to grams.
Since 1 L of water has a mass of 1000 grams, we can convert 300 mg/L to grams by dividing it by 1000.
300 mg/L = 0.3 g/L

Step 3: Multiply the grams per liter by the volume of the water sample.
Since we have a 3L water sample, we can multiply 0.3 g/L by 3 to find the total grams of CaCO3.
0.3 g/L * 3 L = 0.9 g

Therefore, the grams of Calcium Carbonate (CaCO3) in the 3L water sample is 0.9g.

So, the correct answer is option c. 0.30g.

A 3L water sample has a hardness of 300ppm by mass CaCO3. The grams of Calcium Carbonate CaCO3 is:Question 34Select one:a.1.0gb.0.20gc.0.30gd.1.20g

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