What does the following program print?#include <stdio.h>int main() {    int sum = 0;    for (int i = 1; i <= 5; i++) {        sum += i;    }    printf("%d\n", sum);    return 0;}

The program prints the number 15.

Here's the step-by-step explanation:

1. The program starts with the declaration of an integer variable sum and initializes it to 0.

2. Then, a for loop is started where the loop variable i is initialized to 1 and the condition is i less than or equal to 5. This means the loop will run 5 times, with i taking the values 1, 2, 3, 4, and 5 in each iteration.

3. In each iteration of the loop, the current value of i is added to sum. So, in the first iteration, 1 is added to sum, in the second iteration, 2 is added to sum, and so on until in the fifth iteration, 5 is added to sum.

4. After all iterations of the loop, sum contains the sum of the numbers from 1 to 5, which is 1 + 2 + 3 + 4 + 5 = 15.

5. Finally, the printf function is used to print the value of sum, which is 15. So, the output of the program is 15.