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Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the specified axis.x = 5y2,   y ≥ 0,   x = 5;   about y = 2

Question

Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the specified axis.x = 5y2,   y ≥ 0,   x = 5;   about y = 2

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Solution

The method of cylindrical shells is a method for finding the volume of a solid of revolution. The basic idea is to approximate the region by cylinders and then to take the limit as the number of cylinders goes to infinity.

Here are the steps to solve the problem:

  1. Identify the region: The region is bounded by the curves x = 5y^2, y ≥ 0, and x = 5.

  2. Sketch the region: It's always a good idea to sketch the region to get a visual understanding of the problem. You'll see that the region is a parabolic segment.

  3. Set up the integral: We're rotating about the line y = 2, so the radius of a typical shell is |2 - y| and the height is |5 - 5y^2|. The volume of a typical shell is therefore 2π * radius * height = 2π * |2 - y| * |5 - 5y^2|.

  4. Integrate: We need to integrate this expression from y = 0 to y = sqrt(1) to get the total volume. This gives us the integral ∫ from 0 to sqrt(1) of 2π * |2 - y| * |5 - 5y^2| dy.

  5. Evaluate the integral: This integral can be a bit tricky to evaluate, but with some patience and careful algebra, you should find that the volume is 20π/3 cubic units.

This problem has been solved

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Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the y-axis.y = 4e−x2,      y = 0,      x = 0,      x = 1Sketch the region and a typical shell.Step 1Rotating a vertical strip around the y-axis creates a cylinder with radius r = $$x and height h = $$4e−x2 . Sketch the region and a typical shell. Step 2Now we can say that the volume of the solid created by rotating the region under y = 4e−x2and above the x-axis between x = 0 and x = 1 around the y-axis isV = b2𝜋rh dxa= 2𝜋x  dx.

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