If n(A) = 2, P(A) = .!. then n(S) = ?

The question seems to be about probability. However, there seems to be a typo in the probability of A (P(A)) as ".!." is not a valid value.

Assuming you meant P(A) = 0.1, here's how you can find n(S):

1. The probability of an event A is given by P(A) = n(A) / n(S), where n(A) is the number of outcomes in event A and n(S) is the total number of outcomes in the sample space S.

2. You can rearrange this formula to solve for n(S): n(S) = n(A) / P(A)

3. Substituting the given values into this formula gives: n(S) = 2 / 0.1 = 20

So, if n(A) = 2 and P(A) = 0.1, then n(S) = 20.