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When 100V D.C. is applied across a coil, a current of 1A flows through it. When 100V A.C. of 50 Hz is applied to the same coil, only 0.5A flows. The inductance of the coil is :-

Question

When 100V D.C. is applied across a coil, a current of 1A flows through it. When 100V A.C. of 50 Hz is applied to the same coil, only 0.5A flows. The inductance of the coil is :-

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Solution

To find the inductance of the coil, we first need to find the reactance (X) of the coil when the AC voltage is applied.

Reactance (X) is the resistance offered by a coil to the flow of AC current. It is given by the formula:

X = V / I

where V is the voltage and I is the current.

In this case, when the AC voltage is applied, V = 100V and I = 0.5A.

So, X = 100 / 0.5 = 200 ohms.

The reactance of a coil is also given by the formula:

X = 2πfL

where f is the frequency and L is the inductance.

In this case, f = 50Hz. We can rearrange the formula to solve for L:

L = X / (2πf)

Substituting the known values:

L = 200 / (2π * 50) = 200 / (100π) = 2 / π Henry

So, the inductance of the coil is 2 / π Henry.

This problem has been solved

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