A person covers a certain distance with certain speed if he increases his speed by 15 km/hr. Then he will be 16 min. early. By how much time he will be late if he reduces his speed by 12 km/hr, if his initial speed is 60 km/hr?Options15 min25 min24 min20 min

To solve this problem, we need to use the concept of relative speed and time.

Step 1: Calculate the distance covered. The person increases his speed by 15 km/hr and as a result, he saves 16 minutes or 16/60 hours. So, the distance covered is (speed * time) = (60+15) km/hr * (16/60) hr = 20 km.

Step 2: Calculate the time taken with reduced speed. Now, if he reduces his speed by 12 km/hr, his new speed is (60-12) = 48 km/hr. The time taken to cover the same distance is (distance/speed) = 20 km / 48 km/hr = 0.4167 hours.

Step 3: Compare this with the original time. The original time taken to cover the distance at 60 km/hr is (distance/speed) = 20 km / 60 km/hr = 0.3333 hours.

Step 4: Calculate the difference. The difference in time is 0.4167 hours - 0.3333 hours = 0.0834 hours. Convert this to minutes by multiplying by 60, we get 5 minutes.

So, he will be 5 minutes late if he reduces his speed by 12 km/hr. However, this option is not available in the given options. There might be a mistake in the problem or the options provided.