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3 bars of length 16, 20 and 24 cm are cut into equal parts and are packed in a box which can contain maximum of two pieces of such rods. Find the minimum number of boxes required.8126030

Question

3 bars of length 16, 20 and 24 cm are cut into equal parts and are packed in a box which can contain maximum of two pieces of such rods. Find the minimum number of boxes required.8126030

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Solution

To solve this problem, we first need to find the greatest common divisor (GCD) of the lengths of the bars. The GCD will give us the length of the equal parts into which the bars can be cut.

Step 1: Find the GCD of 16, 20, and 24. The GCD of these numbers is 4 cm.

Step 2: Determine how many pieces each bar can be cut into.

  • The 16 cm bar can be cut into 16/4 = 4 pieces.
  • The 20 cm bar can be cut into 20/4 = 5 pieces.
  • The 24 cm bar can be cut into 24/4 = 6 pieces.

Step 3: Calculate the total number of pieces. The total number of pieces is 4 + 5 + 6 = 15 pieces.

Step 4: Determine the number of boxes needed. Since each box can contain a maximum of two pieces, we divide the total number of pieces by 2. So, 15/2 = 7.5.

Since we can't have half a box, we round up to the nearest whole number. Therefore, we need 8 boxes to pack all the pieces.

This problem has been solved

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