An optically active compound (A) is treated with NaI in acetone to form compound (B). Determine the optical activity of compound (B).optically activeoptically inactive and racemic formoptically inactiveNone of these

The reaction you're referring to is a nucleophilic substitution reaction (SN2). In an SN2 reaction, the configuration of the molecule is inverted. However, the optical activity of the product depends on the starting material.

If the starting material (A) is optically active, it means it is chiral and has a non-superimposable mirror image. When it undergoes an SN2 reaction, the configuration at the chiral center is inverted, but it will still be chiral and thus optically active.

However, if the starting material (A) is a racemic mixture (equal amounts of two enantiomers), the product (B) will also be a racemic mixture. A racemic mixture is optically inactive because the rotations of the two enantiomers cancel each other out.

So, without more information about compound (A), it's not possible to definitively answer the question. If (A) is a single enantiomer, (B) will be optically active. If (A) is a racemic mixture, (B) will be optically inactive.