A six-digit number formed by repeating a three-digit number is always exactly divisible by 1001.

Here's why:

1001 is a product of 7, 11, and 13 (i.e., 1001 = 7 * 11 * 13).

Any six-digit number formed by repeating a three-digit number can be expressed as 1001 * k, where k is the three-digit number.

Therefore, such a number is always divisible by 7, 11, 13, and 1001.

Question

A six-digit number formed by repeating a three-digit number is always exactly divisible by 1001.

Here's why:

1001 is a product of 7, 11, and 13 (i.e., 1001 = 7 * 11 * 13).

Any six-digit number formed by repeating a three-digit number can be expressed as 1001 * k, where k is the three-digit number.

Therefore, such a number is always divisible by 7, 11, 13, and 1001.

Knowee AI · Accepted Answer

A six-digit number formed by repeating a three-digit number is always exactly divisible by 1001.

Here's why:

1001 is a product of 7, 11, and 13 (i.e., 1001 = 7 * 11 * 13).

Any six-digit number formed by repeating a three-digit number can be expressed as 1001 * k, where k is the three-digit number.

Therefore, such a number is always divisible by 7, 11, 13, and 1001.

A six digit number is formed by repeating a three digit number; for example, 256256 or 678678 etc. Any number of this form is always exactly divisible by:________7 only11 only13 only1001