Find the volume of a right circular cone that has a height of 12 m and a base with a diameter of 8.9 m. Round your answer to the nearest tenth of a cubic meter.

To find the volume of a right circular cone, we use the formula:

$V = \frac{1}{3} \pi r^2 h$

where $V$ is the volume, $r$ is the radius of the base, and $h$ is the height of the cone.

1. First, determine the radius of the base. The diameter is given as 8.9 meters, so the radius $r$ is half of the diameter:

$r = \frac{8.9}{2} = 4.45 \, \text{m}$

2. The height $h$ is given as 12 meters.

3. Substitute the values of $r$ and $h$ into the volume formula:

$V = \frac{1}{3} \pi (4.45)^2 (12)$

4. Calculate $(4.45)^2$:

$(4.45)^2 = 19.8025$

5. Multiply this result by 12:

$19.8025 \times 12 = 237.63$

6. Now, multiply by $\pi$ (approximately 3.14159):

$237.63 \times 3.14159 \approx 746.9$

7. Finally, divide by 3:

$\frac{746.9}{3} \approx 249.0$

So, the volume of the right circular cone is approximately 249.0 cubic meters.