To determine if the function f(x) = x^2 is one-to-one (injective), we need to check if for every x1 and x2 in the domain (set of integers), f(x1) = f(x2) implies x1 = x2.

Let's take two different integers x1 and x2 such that x1 = -n and x2 = n (where n is a positive integer). Then f(x1) = f(x2) because (-n)^2 = n^2. However, x1 is not equal to x2 because -n is not equal to n.

Therefore, the function f(x) = x^2 is not one-to-one when defined from the set of integers to the set of integers.

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To determine if the function f(x) = x^2 is one-to-one (injective), we need to check if for every x1 and x2 in the domain (set of integers), f(x1) = f(x2) implies x1 = x2.

Let's take two different integers x1 and x2 such that x1 = -n and x2 = n (where n is a positive integer). Then f(x1) = f(x2) because (-n)^2 = n^2. However, x1 is not equal to x2 because -n is not equal to n.

Therefore, the function f(x) = x^2 is not one-to-one when defined from the set of integers to the set of integers.

Knowee AI · Accepted Answer

To determine if the function f(x) = x^2 is one-to-one (injective), we need to check if for every x1 and x2 in the domain (set of integers), f(x1) = f(x2) implies x1 = x2.

Let's take two different integers x1 and x2 such that x1 = -n and x2 = n (where n is a positive integer). Then f(x1) = f(x2) because (-n)^2 = n^2. However, x1 is not equal to x2 because -n is not equal to n.

Therefore, the function f(x) = x^2 is not one-to-one when defined from the set of integers to the set of integers.

Determine whether the function f (x) = x2 from theset of integers to the set of integers is one-to-one

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