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Given the function y=3x2-12x+9, • Place a point on the coordinate grid to show each x-intercept of the function. • Place a point on the coordinate grid to show the minimum value of the function.

Question

Given the function y=3x2-12x+9, • Place a point on the coordinate grid to show each x-intercept of the function. • Place a point on the coordinate grid to show the minimum value of the function.

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Solution

To find the x-intercepts of the function y = 3x^2 - 12x + 9, we need to set y to 0 and solve for x.

0 = 3x^2 - 12x + 9

This is a quadratic equation, and we can solve it by factoring, completing the square, or using the quadratic formula. In this case, factoring is the simplest method:

0 = 3(x^2 - 4x + 3)

0 = 3(x - 1)(x - 3)

Setting each factor equal to zero gives the solutions x = 1 and x = 3. These are the x-intercepts of the function, so we would place points at (1, 0) and (3, 0) on the coordinate grid.

To find the minimum value of the function, we need to find the vertex of the parabola. The x-coordinate of the vertex of a parabola given by the equation y = ax^2 + bx + c is -b/2a. In this case, a = 3 and b = -12, so the x-coordinate of the vertex is -(-12)/(2*3) = 2.

Substituting x = 2 into the equation gives the y-coordinate of the vertex:

y = 3(2)^2 - 12(2) + 9 = -3

So the minimum value of the function is -3, and we would place a point at (2, -3) on the coordinate grid.

This problem has been solved

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